Calculate the total kinetic energy of one kilo mole of Oxygen gas at `27^(@)C`

Explanation

Average kinetic energy per molecule of the gas
`= (3)/(2) (R)/(N) T`
`= (3)/(2) xx (8.314 xx 10^(7))/(6.023 xx 10^(23)) xx 273`
`= 5.65 xx 10^(-14) " erg " = 5.65 xx 10^(-21) J`
Total kinetic energy of 0.5 mole of the gas
`= (3)/(2) RT xx 0.5`
`= (3)/(2) xx 8.314 xx 10^(7) xx 273 xx 0.5`
`= 1.702 xx 10^(10) " erg" = 1.702 kJ`