Calculate the pressure exerted by `10^(23)` gas molecules each of mass `10^(-22) g` in a container of volume 1 litre the rms speed is `10^(5) cm s^(-1)`

Explanation

To calculate the pressure exerted by \(10^{23}\) gas molecules, each with a mass of \(10^{-22}\) g, in a container of volume 1 liter with an rms speed of \(10^{5}\) cm/s, we can use the kinetic gas equation:

\[ P = \frac{1}{3} \frac{m N c^2}{V} \]

where:
- \(P\) = pressure
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