Oxygen at 1 atmosphere and `0^(@)C` has a density of `1.4290 g L^(-1)`. Find the rms speed of oxygen molecule.

Explanation

`P = 1 atm = 101.3 xx 10^(3) Pa`
`d = 1.4290 g L^(-1) = 1.4290 kg m^(-3)`
We know that,
`c = sqrt((3P)/(d)) = sqrt((3 xx 101.3 xx 10^(3))/(1.4290)) = 461.15 ms^(-1)`