Calculate the average kinetic energy per mole of `CO_(2)` gas at `27^(@)C` in different units.

Explanation

`KE = (3)/(2) nRT`
`= (3)/(2) xx 1 xx 1.987 xx 300 = 894.15 cal`
`KE = (3)/(2) nRT`
`= (3)/(2) xx 1 xx 8.314 xx 300`
`= 3741 J`
`= 3.741 xx 10^(10)` erg