Specific heat of a monoatomic gas at constant volume is `315 J kg^(-1) K^(-1)` and at a contant pressure is `525 J kg^(-1) K^(-1)`. Calculate the molar of the gas.

Explanation

`C_(P) = M xx 525 " and " C_(V) = M xx 315` where, M is the molecular mass.
`C_(P) - C_(V) = R (R = 8.314 J K^(-1) mol^(-1))`
`M xx 525 - M xx 315 = 8.314`
`M (525 - 315) = 8.314`
`M = (8.314)/(210) = 0.0396 kg mol^(-1) = 39.6 g mol^(-1)`