An open vessel at `27^(@)C` is heated until `3//5` of the air in it is expelled. Assuming that the volume of the vessel remains constant, find the temperature to which the vessel has been heated.

Answer

`447^(@)C`

Explanation

Both volume and pressure are constant as the vessel is open,
i.e., `n_(1)RT_(1) = n_(2) RT_(2)`
or `(n_(1))/(n_(2)) = (T_(2))/(T_(1))`
If `n_(1) = 1, n_(2) = 1 - (3)/(5) = (2)/(5)`
So, `(5)/(2) = (T_(2))/(300) " or " T_(2) = 750 K = 477^(@)C`