Calculate the compressibility factor for `SO_(2)` if 1 mole of it occupies 0.35 litre at `300K` and 50 atm pressure Comment on the result .

Explanation

`Z = (PV)/(nRT) = (50 xx 0.35)/(1 xx 0.0821 xx 300) = 0.711`
Since, `Z lt 1`, the gas `SO_(2)` will be more compressible than ideal gas