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56 g of nitrogen and 96 g of oxygen are ...

56 g of nitrogen and 96 g of oxygen are mixed isothermally at a total pressure of 10 atm. The partial pressures of oxygen and nitrogen (in atm) are respectively:

A

4, 6

B

5, 5

C

2, 8

D

8, 2

Text Solution

Verified by Experts

The correct Answer is:
A
`n_(N_(2)) = (56)/(28) = 2 , n_(O_(2)) = (96)/(32) = 3`
`P_(N_(2)) = x_(N_(2)) xx P_("Total")`
`= (2)/(2 + 3) xx 10 = 4 atm`
`P_(O_(2)) = 10 - 4 = 6 atm`
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