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For one mole of a van der Waals gas when...

For one mole of a van der Waals gas when `b =0` and `T =30 K` the `PV vs1//V` plot is shown below The value of the van Waals constant a `("atm litre"^(2) mol^(-2))` is
.

A

`1.0`

B

`4.5`

C

`1.5`

D

`3.0`

Text Solution

Verified by Experts

The correct Answer is:
C
The van der Waals' equation for 1 mol gas will be
`[P + (a)/(V^(2))] [V - b] = RT`
Since, `b = 0`
`:. PV = RT - (a)/(V)` (`y = c + MX` from )
When PV is plotted against `(1//V)`, we get straight line with negative slope i.e., `(-a)`
`:.` Slope `= (20.1 - 24.6)/(3)`
`- 1.5`
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