1 litre of `N_(2) " and " 7//8` litre of `O_(2)` at the same temperature and pressure were mixed together. What is the relation between the masses of the two gases in the mixture ?

Options

A. `M_(N_(2)) = 3M_(O_(2))`
B. `M_(N_(2)) = 8M_(O_(2))`
C. `M_(N_(2)) = M_(O_(2))`
D. `M_(N_(2)) = 16 M_(O_(2))`

Answer

C

Explanation

`PV = (M)/(m) RT`
`P xx 1 = (M_(N_(2)))/(28) RT`....(i)
`P xx (7)/(8) = (M_(O_(2)))/(32)RT` ....(ii)
Dividing eq. (i) by e. (ii), we get
`M_(N_(2)) = M_(O_(2))`