Write the balanced ionic equation for the reaction of sodium bicarbonate with sulphuric acid

Explanation

The molecular equation for the chemical change is:
`NaHCO_(3)+H_(2)SO_(4) to Na_(2)SO_(4)+H_(2)O+CO_(2)`
`NaHCO_(3), H_(2)SO_(4) and Na_(2)SO_(4)` are ionic compounds, so these are written in ionic forms:
`Na^(+)+HCO_(3)^(-)+2H^(+)+SO_(4)^(2-)to 2Na^(+)+SO_(4)^(2-)+H_(2)O+CO_(2)`
`Na^(+) and SO_(4)^(2-)` ions are spector ions hence these shall not appear in the final equation.
`HCO_(3)^(-)+2H^(+) to H_(2)O+CO_(2)`
To make equal charges on both sides, `HCO_(3)^(-)` should have a coefficient 2.
`2HCO_(3)^(-)+2H^(+) to H_(2)O+CO_(2)`
In order to balance the hydrogen and carbon on both sides, the molecules of `H_(2)O and CO_(2)` should have a coefficient respectively
`2HCO_(3)^(-)+2H^(+) to 2H_(2)O+CO_(2)`
`HCO_(3)^(-)+H^(+) to H_(2)O+CO_(2)`
This is the balanced ionic equation.