Home
Class 11
CHEMISTRY
Write the following ionic equation in th...

Write the following ionic equation in the molecular form if the reactants are chlorides.
`2Fe^(3+)+Sn^(2+) to 2Fe^(2+)+Sn^(4+)`

Text Solution

Verified by Experts

For writing the reactants in moleuclar forms, the requisite number of chloride ions are added.
`ubrace(2Fe^(3+)+6Cl^(-))+ubrace(Sn^(2+)+2Cl^(-))`
Similarly `8Cl^(-)` ions are added on RHS ot neutralise the charges.
`underset(2FeCl_(2))ubrace(2Fe^(2+)+4Cl^(-))+underset(SnCl_(4))ubrace(Sn^(4+)+4Cl^(-))`
Thus, the balanced molecular equation is
`2FeCl_(3)+SnCl_(2)=2FeCl_(2)+SnCl_(4)`
Promotional Banner

Topper's Solved these Questions

  • OXIDATION AND REDUCTION (REDOX REACTIONS)

    OP TANDON|Exercise ILLUSTRATION|5 Videos

  • OXIDATION AND REDUCTION (REDOX REACTIONS)

    OP TANDON|Exercise Practise Problems|5 Videos

  • MISCELLANEOUS (TOPICS OF GENERAL INTEREST)

    OP TANDON|Exercise SET-VI: Problems on graphical aptitude|53 Videos

  • POLYMERS

    OP TANDON|Exercise PASSAGE 3|5 Videos

Similar Questions

Explore conceptually related problems

Write the half reaction for the reaction 2Fe^(+3) + 2I^(-) to 2Fe^(+2) + I_(2)

The missing tenn in the following equation is: 2Fe^(3+)+Sn^(2+) to 2Fe^(2+)+...

Consider the following E^(@) values. E^(@)underset(M^(3+)//M^(2-)) values for Cr, Mn, Fe and Co are -0.41 Under standard condition, the potential for the reaction : Sn(s) + 2Fe^(3+)(aq) rightarrow2Fe^(2+)(aq) + Sn^(2+)(aq)

Balance the following equations by oxidation number method: a. Fe^(2+) + Sn^(+2) rarr Sn^(4+) + fe^(2+) b. MnO_(4)^(Ө) + H_(2)S rarr S+Mn^(2+) c. Cr_(2)O_(7)^(2-) + 2I^(Ө) rarr 2Cr^(3+) + I_(2) d. Zn + NO_(3)^(Ө) rarr Zn^(2+) + NH_(4)^(o+) e. MnO_(4)^(Ө)+SO_(3)^(2-) rarr SO_(4)^(2-)+MnO_(2) f. Cl_(2)+IO_(3)^(Ө) rarr IO_(4)^(Ө) (in basic medium)

Calculate at 25^(@) C , the equilibrium constant for the reaction : 2 Fe^(3+) + Sn^(2+) hArr 2 Fe^(2+) + Sn^(4+) Given that E_((Fe^(3+)|Fe^(2+)))^(Theta) = 0.771 V , E_((Sn^(4+) |Sn^(2+)))^(Theta) = 0.150 V

Consider the following E^(@) values E^(@) values E_(Fe^(3+)//Fe^(2+))^(@)= 0.77v , E_(Sn^(2+)//Sn)^(@) = -0.14 under standard condition the potential for the reaction Sn_(s)+ 2Fe^(3+)(aq)rightarrow 2Fe^(2+)(aq) + Sn^(2+) (aq) is :

Sn1 and Sn2 reaction