Balance the followin equation by oxidation number method:
`I_(2)+NaOH to NaIO_(3)+NaI+H_(2)O`

Explanation

To balance the equation \( I_2 + NaOH \rightarrow NaIO_3 + NaI + H_2O \) using the oxidation number method, follow these steps:

### Step 1: Assign Oxidation Numbers
- For \( I_2 \): The oxidation state of iodine (I) is 0.
- For \( NaOH \): Sodium (Na) is +1, Oxygen (O) is -2, and Hydrogen (H) is +1.
- For \( NaIO_3 \): Sodium (Na) is +1, Oxygen (O) is -2 (3 oxygen gives -6), so the oxidation state of iodine (I) is +5.
- For \( NaI \): Sodium (Na) is +1, and iodine (I) is -1.
- For \( H_2O \): Hydrogen (H) is +1 and Oxygen (O) is -2.
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