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Balance the following equation by oxidat...

Balance the following equation by oxidation number method
`HgS+HCl+HNO_(3) to H_(2)HgCl_(4)+NO+S+H_(2)O`

Text Solution

Verified by Experts

Writing the oxidation numbers of the atoms.
`overset(+2 +2)(HgS)+overset(+1 -1)(HCl)+overset(+1 +5 -2)(HNO_(3)) to overset(+1 +2 -1)(H_(2)HgCl_(4))+overset(+2 -2)(NO)+overset(0)(S)+overset(+1 -2)(H_(2)O)`
The oxidation number of S and N have changed
`overset(-2)(HgS) to overset(0)(S) ...(i) `
`overset(+5)(HNO_(3)) to overset(+2)(NO) ....(ii)`
Increase in Ox. no. of S=2 units per HgS molecule
Decrease in Ox. no of N=3 units per `HNO_(3)` molecule
Multiplying eq. (i) by 3 and eq. (ii) by 2 as to make increase and decrease equal.
`3HgS+2HNO_(3) to 3S+2NO`
Balancing Hg and chlorine.
`3HgS+2HNO_(3)+12HCl to 3H_(2)HgCl_(4)+3S+2NO`
To balance hydrogen and oxygen, `4H_(2)O` molecules are added on RHS. Hence, the balanced equation is.
`3HgS+2HNO_(3)+12 HCl to 3H_(2)HgCl_(4)+3S+2NO+4H_(2)O`
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