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OP TANDON-OXIDATION AND REDUCTION (REDOX REACTIONS)-LEVEL A
- In this reaction 2Na(2)S(2)O(3)+I(2)=Na(2)SO(4)O(6)=2NaI(2) acts as:
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- The most common oxidation explained as due to:
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- Select the compound in which chlorine shows oxidation state +7:
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- HBr and HI can reduce sulphurie acid, HCI can reduced KMnO(4) and HF c...
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- One mole of N(2)H(4) loses ten moles of electrons to form a new compou...
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- The brown ring complex compound of iron is formulated as [Fe (H(2)O)(5...
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- In which of the following compounds, iron has an oxidation state of+3?
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- When KMnO(4) is reduced with oxalic acid in acidic solution, the oxida...
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- In which of the following reactions the underlined substance is oxidis...
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- When tin(IV) chloride is treated with excess of conc., hydrochloric ac...
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- In the following reaction 3Br(2)+6CO(3)^(2-)+3H(2)O=5Br^(-)+BrO(3)^(...
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- The oxidation state of phosphorus varies from:
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- When SO(2) is passed through acidic solution of potassium dichromate, ...
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- Oxidation states of iodine vary from
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- Oxidation number of fluorine in F(2)O is:
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- In that compounds KMnO(4) and K(2)Cr(2)O(7) the highest oxidation stat...
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- Cl(2)+H(2)S to 2HCl+S, In that above reaction oxidation state of chl...
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- Carbon is in highest oxidation state in:
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- Addition of iron or zinc to copper sulphate cause, precipitation of c...
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- In a reaction H(2)O("steam")+C("glowing")=CO+H(2)
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