Addition of iron or zinc to copper sulphate cause, precipitation of copper owing to the:

Options

A. reduction of `Cu^(2+)`
B. oxidation of `Cu^(2+)`
C. hydrolysis of `CuSO_(4)`
D. ionisationn of `CuSO_(4)`

Answer

To solve the question regarding the addition of iron or zinc to copper sulfate causing the precipitation of copper, we can break down the process step by step:

### Step-by-Step Solution:

1. **Identify the Reaction**: When iron (Fe) or zinc (Zn) is added to copper sulfate (CuSO₄), a displacement reaction occurs. This means that the more reactive metal (Fe or Zn) displaces the less reactive metal (Cu) from its compound.

2. **Write the Initial Equation**: The initial state of the reaction can be represented as:
\[ \text{CuSO}_4 (aq) + \text{Fe (s)} \rightarrow \text{Cu (s)} + \text{FeSO}_4 (aq) \]
or
\[ \text{CuSO}_4 (aq) + \text{Zn (s)} \rightarrow \text{Cu (s)} + \text{ZnSO}_4 (aq) \]

3. **Determine Oxidation States**: In copper sulfate (CuSO₄), copper is in the +2 oxidation state (Cu²⁺). When copper is precipitated, it is in the elemental form with an oxidation state of 0 (Cu).

4. **Identify the Change in Oxidation State**: The change in oxidation state for copper can be summarized as:
\[ \text{Cu}^{2+} \rightarrow \text{Cu}^0 \]
This indicates that copper is being reduced, as its oxidation state decreases from +2 to 0.

5. **Conclusion**: Since the oxidation state of copper decreases, we conclude that copper ions (Cu²⁺) are being reduced to copper metal (Cu). Therefore, the correct answer to the question is that the precipitation of copper occurs owing to the reduction of Cu²⁺ ions.

### Final Answer:
The precipitation of copper occurs owing to the reduction of Cu²⁺ ions.

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