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The number of moles of K(2)Cr(2)O(7) red...

The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions is

A

`(1)/(3)`

B

`(3)/(2)`

C

`(5)/(2)`

D

`(6)/(5)`

Text Solution

Verified by Experts

The correct Answer is:
A
Balanced equation is:
`Cr_(2)O_(7)^(2+)+14H^(+)+3Sn^(2+) to 2CrO_(7)^(2-)`
1 mole of `Sn^(2+) -=(1)/(3)"mole of" Cr_(2)O_(7)^(2-)`
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OP TANDON-OXIDATION AND REDUCTION (REDOX REACTIONS)-SECTION B
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