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Fe^(3+) is reduced to Fe^(2+) of NaOH...

`Fe^(3+)` is reduced to `Fe^(2+)` of NaOH

A

`H_(2)O_(2)` is presence of NaOH

B

`Na_(2)O_(2)` in water

C

`H_(2)O_(2)` in presence of `H_(2)SO_(4)`

D

`Na_(2)O_(2)` in presence of `H_(2)SO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A, B
In basic medium `H_(2)O_(2)` acts as reducing agent.
`Na_(2)O_(2)+2H_(2)O to 2NaOH+H_(2)O_(2)`
`2Fe^(3+)+H_(2)O_(2)+2OH^(-) to 2Fe^(2+)+2H_(2)O+O_(2)`
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