Home
Class 11
CHEMISTRY
The valancy of carbons is generally 4, b...

The valancy of carbons is generally `4`, but its oxidation state may be `-4, -2, 0, +2, -1`, etc. In the compounds containing `C, H`, and `O`, the oxidation number of `C` is calculated as
Oxidation number of `C= (2n_(O)-n_(H))/(n_(C ))`
Where `n_(O), n_(H)` and `n_(C )` are the numbers of oxygen, hydrogen, and carbons, atoms, respectively.
In which of the following compounds is the oxidation state of carbon is zero?

A

`CH_(4)`

B

`CH_(3)OH`

C

`CH_(2)O`

D

HCOOH

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • OXIDATION AND REDUCTION (REDOX REACTIONS)

    OP TANDON|Exercise Self assignment|22 Videos

  • OXIDATION AND REDUCTION (REDOX REACTIONS)

    OP TANDON|Exercise SECTION V|3 Videos

  • OXIDATION AND REDUCTION (REDOX REACTIONS)

    OP TANDON|Exercise INTEGER TYPE|11 Videos

  • MISCELLANEOUS (TOPICS OF GENERAL INTEREST)

    OP TANDON|Exercise SET-VI: Problems on graphical aptitude|53 Videos

  • POLYMERS

    OP TANDON|Exercise PASSAGE 3|5 Videos

Similar Questions

Explore conceptually related problems

The valancy of carbons is generally 4 , but its oxidation state may be -4, -2, 0, +2, -1 , etc. In the compounds containing C, H , and O , the oxidation number of C is calculated as Oxidation number of C= (2n_(O)-n_(H))/(n_(C )) Where n_(O), n_(H) and n_(C ) are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. In which of the following compounds is the oxidation state of C highest?

The valancy of carbons is generally 4 , but its oxidation state may be -4, -2, 0, +2, -1 , etc. In the compounds containing C, H , and O , the oxidation number of C is calculated as Oxidation number of C= (2n_(O)-n_(H))/(n_(C )) Where n_(O), n_(H) and n_(C ) are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. In which of the following compounds is the oxidation state of C a fraction?

The valancy of carbons is generally 4 , but its oxidation state may be -4, -2, 0, +2, -1 , etc. In the compounds containing C, H , and O , the oxidation number of C is calculated as Oxidation number of C= (2n_(O)-n_(H))/(n_(C )) Where n_(O), n_(H) and n_(C ) are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. In which of the following compounds is the valency of C two?

The valancy of carbons is generally 4 , but its oxidation state may be -4, -2, 0, +2, -1 , etc. In the compounds containing C, H , and O , the oxidation number of C is calculated as Oxidation number of C= (2n_(O)-n_(H))/(n_(C )) Where n_(O), n_(H) and n_(C ) are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. Teh oxidation of C in diamonds is

Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms In which of the following compounds, the valency of carbon is two?

Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms Which of the following compounds have zero oxidation state at carbon

Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms Which of the following oxides of carbon has fractional oxidation state?

Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms Oxidation state of carbon in diamond is:

Calculate the oxidation number of C in C_6H_(12)O_6 .