Calculate the number of millimoles and milliequivalents of `Cr_(2)O_(7)^(2-)` ions in acid medium when 100 mL of `0.01 M Cr_(2)O_(7)^(2-)` is reduced to `Cr^(3+) " by " Fe^(2+)`.
Text Solution
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`underset(1 " mol")(Cr_(2)O_(7)^(2-))+14 H^(+) + underset(6 " mol")(6e^(-)) to 2Cr^(3+)+7H_(2)O` `therefore " " 0.01 M Cr_(2)O_(7)^(2-)-= 0.06 N Cr_(2)O_(7)^(2-)` Number of millimoles `=Mxx V=0.01xx100=1` Number of milliequivalents `=N xxV =0.06xx100=6`
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