Home
Class 11
CHEMISTRY
4.9 g of H(2)SO(4) is present in 100 mL ...

4.9 g of `H_(2)SO_(4)` is present in 100 mL of the solution. What is the molarity of the solution ? Calculate its normality also.

Text Solution

AI Generated Solution

To find the molarity and normality of the `H₂SO₄` solution, we can follow these steps: ### Step 1: Calculate the Strength of the Solution The strength of the solution is given in grams per liter. Since we have 4.9 g of `H₂SO₄` in 100 mL, we need to convert this to grams per liter. \[ \text{Strength (g/L)} = \frac{\text{mass (g)}}{\text{volume (L)}} \] ...
Promotional Banner

Topper's Solved these Questions

  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Example 9|2 Videos
  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Example 10|2 Videos
  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Example 1|2 Videos
  • THE COLLOIDAL STATE

    OP TANDON|Exercise Self Assessment|21 Videos

Similar Questions

Explore conceptually related problems

6.8 g H_(2)O_(2) present in 100 mL of its solution. What is the molarity of solution?

0.8g of H_(2)SO_(4) is present in 2 litres of a solution. The molarity of the solution is

4.9 g of sulphuric acid is present in 500 mL of the solution. Calculate the pH of the solution.

18g of glucose (molar mass 180g "mol"^(-1) ) is present in 500CM^(3) of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?

If 36.0 g of glucose is present in 400 ml of solution, molarity of the solution is

If 0.56 g KOH is present in 100 mL of solution, then its normality will be