Hydroxylamine reduces `Fe^(3+)` accoeding to the following reaction:
`2NH_2OH+4Fe^(3+)toH_2O+4Fe^(2+)+4H^(o+)+N_2O`
`Fe^(2+)` produced is is estimated by titration with `KMnO_4` solution A 10 mL sample of `NH_2OH` is diluted to 1000 mL. 50 " mL of " this diluted sample is boiled with excess of Fe (III) solution. The resulting solution required 12 " mL of " 0.02 M `KMnO_4` for complete oxidation. Determine the strength of `NH_2OH`.

Explanation

12 mL of `0.02 M KMnO_(4)-=12 mL " of " 0.1 N KMnO_(4)`
`-=12 mL " of" 0.1 N Fe^(2+)`
`-=12 mL " of " 0.1N NH_(2)OH`
Eq. mass of `NH_(2)OH=("Mol.mass")/(2)=(33)/(2)=16.5`
Mass of `NH_(2)OH` in 12 mL of 0.1 N `NH_(2)OH` soln.
`=(Nxx E xx V)/(1000)=(0.1xx16.5xx12)/(1000)=0.0198 g`
50 mL of diluted solution contains `NH_(2)OH`
`=(0.0198)/(50)xx1000=0.396 g`
10 mL of original solution contains `NH_(2)OH=0.396 g`
1000 mL of original solution contains `NH_(2)OH`
`=100xx0.396=39.6 g`