Number of moles of `K_(2)Cr_(2)O_(7)` that can be reduced by 1 mole of `Sn^(2+)` ions is :

Options

A. `1//3`
B. `3//2`
C. `5//6`
D. `6//5`

Answer

A

Explanation

The redox reaction is :
`Cr_(2)O_(7)^(2-)+14H^(+) +3Sn^(2+) to 2Cr^(3+)+7H_(2)O+3Sn^(4+)`
`therefore 1 " mole of " Sn^(2+)` will reduce `1//3 " mole of " K_(2)Cr_(2)O_(7)`