Home
Class 11
CHEMISTRY
100 mL each of 1NH(2)O(2) " and " 11.2 V...

100 mL each of `1NH_(2)O_(2) " and " 11.2 V H_(2)O_(2)` solution are mixed, then the resultant solution will be :

A

`3M H_(2)O_(2)`

B

`0.5 N H_(2)O_(2)`

C

`25.5 g//L H_(2)O_(2)`

D

`2.55 g//L H_(2)O_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`11.2V H_(2)O_(2)-=(11.2)/(5.6)N H_(2)O_(2) i.e., 2N H_(2)O_(2)`
`N_(1)V_(1)+N_(2)V_(2)=N_(R )(V_(1)+V_(2))`
`1xx100+2xx100=N_(R )xx200`
`N_(R )=(3)/(2)=1.5`
Strength `=N xx " Equivalent mass"`
`=1.5xx17=25.5 g//L`
Promotional Banner

Topper's Solved these Questions

  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Assertion-Reason Type Questions|10 Videos

  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Integer Answer Type Questions|3 Videos

  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Objective Question (Level-A)|99 Videos

  • THE COLLOIDAL STATE

    OP TANDON|Exercise Self Assessment|21 Videos

Similar Questions

Explore conceptually related problems

100mL each of 1N H_(2)O_(2) and 11.2VH_(2)O_(2) solution are mixed, then the final solution is equivalent to: (Assume 1 mole od an ideal gas occupies 22.4L at STP)

When 100 ml of 10 M solution of H_(2)SO_(4) and 100 ml of 1 0 M solution of NaOH are mixed the resulting solution will be

When 100 ml of 10M solution of H_(2)SO_(4) and 100ml of 1M solution of NaOH are mixed the resulting solution will be

The amount of H_(2)O_(20 present in 1L of 1.5 NH_(2)O_(2) solution is

If 100 mL of 1NH_(2)SO_(4) is mixed with 100 mL of 1 M NaOH solution. The resulting solution will be

If 100 mL of H_(2) SO_(4) and 100 mL of H_(2)O are mixed, the mass percent of H_(2) SO_(4) in the resulting solution (d_(H_(2)SO_(4)) = 0.09 g mL^(-1), d_(H_(2)O) = 1.0 mL^(-1))

If 100 mL of 1 N H_(2)SO_(4) is mixed with 100 mL of 1 M NaOH solution. The resulting solution will be

50 ml of '20 V' H_(2)O_(2) is mixed with 200 ml, '10 V' H_(2)O_(2). The volume strength of resulting solution is:

OP TANDON-VOLUMETRIC ANALYSIS-Objective Question (Level-B)
  1. Potassium permanganate acts as an oxidising agent in acidic, alkaline ...

    Text Solution

    |

  2. The number of equivalents of Na(2)S(2)O(3) required for the volumetric...

    Text Solution

    |

  3. The equivalent mass of MnSO(4) becomes half of its molecular mass when...

    Text Solution

    |

  4. A solution of 10 mL of (M)/(10) FeSO(4) was titrated with KMnO(4) solu...

    Text Solution

    |

  5. Among the following reactions, used in titrations, select the reaction...

    Text Solution

    |

  6. Oxalic acid dihydrate, H(2)C(2)O(4). 2H(2)O(s) is often used as a prim...

    Text Solution

    |

  7. A 20 mL sample of a Ba(OH)(2) solution is titrated with 0.245 M HCl. I...

    Text Solution

    |

  8. A solution of which substance can best be used as both titrant and its...

    Text Solution

    |

  9. A 0.2 g sample of benzoic acid, C(6)H(5)COOH, is titrated with a 0.120...

    Text Solution

    |

  10. What mass of magnesium hydroxide is required to neutralise 125 mL of 0...

    Text Solution

    |

  11. In the titration of K(2)Cr(2)O(7) and FeSO(4), the following data is o...

    Text Solution

    |

  12. When 20 mL of (M)/(10) NaOH are added to 10 mL of (M)/(10)HCl, the res...

    Text Solution

    |

  13. A sample of coconut oil weighing 1.5763 g is mixed with 25 mL of 0.421...

    Text Solution

    |

  14. 12.5 mL of a solution containing 6 g of a dibasic acid in one litre wa...

    Text Solution

    |

  15. 20 mL of 0.1 M H(3)BO(3) solution on complete neutralisation requires ...

    Text Solution

    |

  16. The ammonia evolved from the treatment of 0.30 g of an organic compoun...

    Text Solution

    |

  17. A solution contains Na(2)CO(3) " and " NaHCO(3), 10 mL of this solutio...

    Text Solution

    |

  18. MnO(4)^(-) ions are reduced in acidic condition to Mn^(2+) ions wherea...

    Text Solution

    |

  19. 100 mL each of 1NH(2)O(2) " and " 11.2 V H(2)O(2) solution are mixed, ...

    Text Solution

    |

  20. 0.1 g KIO(3) and excess KI when treated with HCl, the iodine is libera...

    Text Solution

    |