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The Langmuir adsorption isotherm is dedu...

The Langmuir adsorption isotherm is deduced using the assumption.

A

the adsorption sites are equivalent in their ability to adsorb the particles

B

the heat of adsorption vaies with coverage

C

the adsorbed molecules interact with each other

D

the adsorption take place in multilayers

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The correct Answer is:
A
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Freundlich adsorption isotherm is

Langmuir adsorption isotherm is best suitable for

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) Freundlich adsorption isotherm is valid for chemisorption . (a) True (b) False

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) In the mathematical relation of Freundlich adsorption isotherm ,the value of (1/n) is 0 le (1)/(n) le 1 . (a) True (b) False

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) The degree of adsorption (x/m) at low pressure will be : (x)/(m) =a (a) True (b) False

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) When "log"((x)/(m)) is plotted against log P, we get a straight line with slope (1/n). (a) True (b) False

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) When ((x)/(m)) is plotted against (1)/(p) ,we get a straight line slope (1/a) and intercept (b/a). (a) True (b) False

What is an adsorption isotherm ?

For Langmuir adsorption isotherm, which is correct?

OP TANDON-ADSORPTION AND CATALYSIS-OBJECTIVE QUESTIONS (LEVEL-A)
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  13. For a linear plot of log (x//m) versus log [ in a Freundlich adsorptio...

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