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Freundlich adsorption isotherm is obeyed...

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure
The relation of Freundlich adsorption isotherm is :
`(x)/(m)=kP^(1//n)`
where ,K and n are constants.
Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is :
`(x)/(m) = (aP)/(1+bP)`
When `((x)/(m))` is plotted against `(1)/(p)` ,we get a straight line slope (1/a) and intercept (b/a).
(a) True (b) False

Text Solution

Verified by Experts

The correct Answer is:
a
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Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) When "log"((x)/(m)) is plotted against log P, we get a straight line with slope (1/n). (a) True (b) False

The equation for Freundlich adsorption isotherm is

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Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) The degree of adsorption (x/m) at low pressure will be : (x)/(m) =a (a) True (b) False

Freundlich adsorption isotherm is obeyed by the adsorption where the adsorbate forms a multimolecular layer on the surface of adsorbent .In such cases, the degree of adsorption varies linearly with pressure but at high pressure, it becomes independent of pressure The relation of Freundlich adsorption isotherm is : (x)/(m)=kP^(1//n) where ,K and n are constants. Langmuir adsorption isotherm is obeyed by the adsorption where the adsorbate forms only a unimolecular adsorbed layer. The mathematical relation of Langmuir isotherm is : (x)/(m) = (aP)/(1+bP) In the mathematical relation of Freundlich adsorption isotherm ,the value of (1/n) is 0 le (1)/(n) le 1 . (a) True (b) False

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What is the slope of freundlich adsorption isotherm ?