The dipole moment of `LiH` is `1.964 xx10^(-29)C-m` and the interatomic diatance between `Li` and `H` in this molceule is `1.596Å` .What is the per cent ionic character in `LiH`.

Explanation

`mu =qxxd`
`=(1.602xx10^(-19)C)xx(1.596xx10^(-10)m)`
`=2.557xx10^(-29) C-m`
% Ionic character =`(mu_("actual"))/(mu_("calculated"))xx100`
`=(1.964xx10^(-29))/(2.577xx10^(-29))xx100`
`=76.8`