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Kinetic energy of 0.3 mole of 'He' gas i...

Kinetic energy of 0.3 mole of 'He' gas in a container of maximum capacity of 4 litre at 5 atm, must be :
`(R = 0.821"atm litre mol"^(-1) K^(-1))`

A

30 atm litre

B

100 atm litre

C

9 atm litre

D

11.11 atm litre

Text Solution

Verified by Experts

The correct Answer is:
A
`PV = (1)/(3)mnc^(2)`
`(3)/(2)PV = (1)/(2)mnc^(2) = KE`
`KE =(3)/(2)PV = (3)/(2) xx 5 xx 4 = 30 "atm litre"`
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