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The rms speed at NTP of a gas can be cal...

The rms speed at NTP of a gas can be calculated from the expression:

A

`sqrt(3P//d)`

B

`sqrt(3PV//M)`

C

`sqrt(3RT//M)`

D

`sqrt(3d//P)`

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The correct Answer is:
To calculate the root mean square (rms) speed of a gas at Normal Temperature and Pressure (NTP), we can use the following steps: ### Step-by-Step Solution: 1. **Understanding RMS Speed**: The rms speed (v_rms) of a gas is given by the formula: \[ v_{rms} = \sqrt{\frac{3P}{D}} \] where P is the pressure of the gas and D is the density of the gas. 2. **Relating Density to Mass and Volume**: We know that density (D) can be expressed as: \[ D = \frac{m}{V} \] where m is the mass of the gas and V is its volume. 3. **Substituting Density into the RMS Speed Formula**: By substituting the expression for density into the rms speed formula, we get: \[ v_{rms} = \sqrt{\frac{3P}{\frac{m}{V}}} = \sqrt{\frac{3PV}{m}} \] 4. **Using the Ideal Gas Law**: The ideal gas law states that: \[ PV = nRT \] where n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin. 5. **Substituting PV in the RMS Speed Formula**: From the ideal gas law, we can express PV as: \[ PV = nRT \] Therefore, we can substitute this into our rms speed equation: \[ v_{rms} = \sqrt{\frac{3(nRT)}{m}} \] 6. **Relating Moles to Mass**: The number of moles (n) can be related to mass (m) using the molar mass (M): \[ n = \frac{m}{M} \] Substituting this back into the equation gives: \[ v_{rms} = \sqrt{\frac{3\left(\frac{m}{M}\right)RT}{m}} = \sqrt{\frac{3RT}{M}} \] 7. **Final Expression for RMS Speed**: Thus, the final expression for the rms speed of a gas at NTP is: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \] ### Summary of the Expression: The rms speed of a gas at NTP can be calculated using the formula: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \]
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