The line through point `(m,-9)` and `(7,m)` has slope `m.` The y-intercept of this line, is

The line through the points (m, -9) and (7, m) has slope m. Then, the x - intercept of this line is

The line through the points (m, -9) and (7, m) has slope m. Then, the x - intercept of this line is

Find the slope and y-intercept of the line : y = 4

The slope of the line y=2020 is m_(1) and the slope of the line joining the points (-5,1) and (3,-5) is m_(2), and the x-intercept of line 2x-3y+5=0 is a , then the value of (m_(1)times m_(2))^(a)=

A line passes through points A(x_1,y_1) and B(h,k) .If the slope of the line is m then show that k-y_1=m(h-x_1)

If a line passing through a point (k,2) and having x- intercept 4 has slope 1/3 find K.

Find the slope,x-intercept and y-intercept of the line 5x+7y-35=0

The lines y=mx+b and y=bx+m intersect at the point (m-b,9) .The sum of the x intercepts of the lines is

If the slope of line is -(7)/(4) and a point on the line is (4, 7) , what is the y-intercept of the line?

m_(1) and m_(2) be slope of lines through the point A(1,1) so that it's intersection point P with line x+y=4 at distance of (2sqrt(2))/((sqrt(3)) unit from A then value of ((m_(1)+m_(2)))/(m_(1)m_(2)) is -