If `A={x|-1 <= x <= 1}=B` then find out which function is one-one, into or one-one onto defined from A to B :

If A =(x+1)/(x-1) and B = (x-1)/(x+1) , then A + B is:

If f(x)=(x-1)/(x+1) , then f(f(a x)) in terms of f(x) is equal to (a)(f(x)-1)/(a(f(x)-1)) (b) (f(x)+1)/(a(f(x)-1)) (f(x)-1)/(a(f(x)+1)) (d) (f(x)+1)/(a(f(x)+1))

If f(x)=(x-1)/(x+1) , then f(f(a x)) in terms of f(x) is equal to (a)(f(x)-1)/(a(f(x)-1)) (b) (f(x)+1)/(a(f(x)-1)) (f(x)-1)/(a(f(x)+1)) (d) (f(x)+1)/(a(f(x)+1))

If f(x)= |1 x x+1 2x x(x-1)(x+1)x3x(x-1)x(x-1)(x-2)(x+1)x(x-1)| then f(500) is equal to a. 0 b. 1 c. 500 d. -500

If f(x)= |1 x x+1 2x x(x-1)(x+1)x3x(x-1)x(x-1)(x-2)(x+1)x(x-1)| then f(500) is equal to a. 0 b. 1 c. 500 d. -500

If f(x)=|1x x+1 2x x(x-1)(x+1) x3 x(x-1) x(x-1)(x-2) (x+1)x(x-1)| then f(500) is equal to 0 b. 1 c. 500 d. -500

If A= |(x,1,1),(1,x,1),(1,1,x)| and B = |(x,1),(1,x)|, " then " (dA)/(dx) =

If f(x)=(x-1)/(x+1), then f(f(ax)) in terms of f(x) is equal to (a) (f(x)-1)/(a(f(x)-1)) (b) (f(x)+1)/(a(f(x)-1))(c)(f(x)-1)/(a(f(x)+1))(d)(f(x)+1)/(a(f(x)+1))