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If the error in measuring the radius of ...

If the error in measuring the radius of the sphere is 2% and that in measuring its mass is 3%, Then the error in measuring the density of material of the sphere is:

A

0.05

B

0.07

C

0.09

D

0.11

Text Solution

Verified by Experts

The correct Answer is:
C

As density `=("mass")/("volume")`
`thereforerho=(M)/((4)/(3)piR^(3))=(3)/(4)(M)/(piR^(3))`
`therefore` The percentage error in density is
`(Deltarho)/(rho)xx100%=((DeltaM)/(M)+3(DeltaR)/(R))xx100%`
`=3%+3(2%)=3%+6%=9%`
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Knowledge Check

  • The error in measurement of radius of a sphere is 0.1% then error in its volume is -

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    B
    `0.4%`
    C
    `0.6%`
    D
    `0.8%`
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