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A block of mass m rests on a rough incli...

A block of mass m rests on a rough inclined plane. The coefficient of friction between the surface and the block is `µ`. At what angle of inclination `theta` of the plane to the horizontal will the block just start to slide down the plane?

A

`theta=tan^(-1)mu`

B

`theta=cos^(-1)mu`

C

`theta=sin^(-1)mu`

D

`theta=sec^(-1)mu`

Text Solution

Verified by Experts

The correct Answer is:
A
The various forces acting on the block are as shown in the figure. From figure `mg sin theta=f…(i)`
`mg cos theta=N..(ii)`
Divide (i) by (ii), we get
`tan theta =(f)/(N)=(muN)/(N) or theta=tan^(-1)(mu)`
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