A block of mass `10kg` is placed on a rough horizontal surface having coefficient of friction `mu=0.5` . If a horizontal force of `100N` is acting on it, then acceleration of the block will be.

Options

A. `10"ms"^(-2)`
B. `5"ms"^(-2)`
C. `15"ms"^(-2)`
D. `0.5"ms"^(-2)`

Answer

B

Explanation

Here, m=10kg, `g=10ms^(-2), mu=0.5, F=100N`
Force of friction `f=muN=mumg=0.5xx10kgxx10ms^(-2)=50N`
Force that produces acceleration `f=F-f=100N-50N=50N`
`a=(F')/(m)=(50N)/(10kg)=5ms^(-2)`