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The mass of a bicycle rider along with t...

The mass of a bicycle rider along with the bicycle is 100 kg. he wants to cross over a circular turn of radius 100 m with a speed of `10 ms^(-1)`. If the coefficient of friction between the tyres and the road is 0.6, will the rider be able to cross the turn? Take `g = 10 ms^(-2)`.

A

300N

B

600N

C

1200N

D

150N

Text Solution

Verified by Experts

The correct Answer is:
B
Centripetal force `=(mv)^(2)/(r)=(100xx10xx10)/(100)=100N`
Required frictional force to cross the turn `=mumg=0.6xx100xx10=600N`
As the friciton force is greater than the centripetal force, so the rider will be able to cross the turn.
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