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A cricket ball of mass 150 g has an init...

A cricket ball of mass 150 g has an initial velocity `bar(u)=(3hati-4hatj)ms^(-1)` and a final velocity `bar(v)=-(3hati-4hatj)ms^(-1)` after being hit. The change in momentum (final momentum -initial momentum) is `("in kg ms"^(-1))`

A

zero

B

`-(0.45hati+0.6hatj)`

C

`-(0.9hati+1.2hatj)`

D

`-5(hati+hatj)`

Text Solution

Verified by Experts

The correct Answer is:
C
Here, m=150g =0.15kg
`bar(u)=(3 hati+4 hatj)ms^(-1)`
`bar(v)=-(3 hati+4 hatj)ms^(-1)`
Initial momentum, `bar(p)_(i)=mbar(u)`
`bar(p)_(f)=(0.15kg) (3 hati+4 hatj)ms^(-1)=(0.45hati+0.6hatj)kg ms^(-1)`
Final momentum, `bar(p)_(i)=mbar(u)`
`bar(p)_(f)=(0.15kg)(-3hati-4hatj)ms^(-1)`
`=-(-0.45hati-0.6 hatj)kg ms^(-1)`
Change in momentum, `Deltabar(p)=bar(p)_(f)-bar(p)_(i)`
`=(-0.45hati-0.6hatj)kg ms^(-1) -(0.45 hati+0.6 hatj) kg ms^(-1)`
`=(-0.9hati+1.2hatj)kg ms^(-1) `
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