An object of mass m is released from rest from the top of a smooth inclined plane of height h. Its speed at the bottom of the plane is proportional to

Options

A. `m^0`
B. `m`
C. `m^2`
D. `m^(-1)`

Answer

A

Explanation

Let v be the speed of the object at the bottom of the plane.
According to work-energy theorem
`W = DeltaK = K_f- K_i`
`mgh=1/2mv^2-1/2m u^2 " " (therefore u=0)`
`mgh=1/2 mv^2 "or" v=sqrt(2gh)`
From this expression, it is clear that v is independent of the mass of an object.