The figure shows elliptical orbit of a planet m about the sun S. the shaded area SCD is twice the shaded area SAB. If `t_(1)` be the time for the planet to move from C to D and `t_(2)` is the time to move from A to B, then:

Options

A. `t_(1)=t_(2)`
B. `t_(1)=2t_(2)`
C. `t_(1)=4t_(2)`
D. `t_(1) gt t_(2)`

Answer

B

Explanation

(b) According to Kepler's second law, equal areas are swept in equal intevals of time .
As area SCD= 2 area SAB, hence `t_(1)=2t_(2)`