A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth, where R is the radius of the earth. The time period of another satellite at a height of 2.5 R from the surface of the earth is …… hours.

Options

A. `3sqrt(2)h`
B. `1.5sqrt(2)h`
C. `6sqrt(2)h`
D. `12sqrt(2)h`

Answer

C

Explanation

( c) Here, `r_(1)=6R+R=7R,T_(1)=24h`
`r_(2)=2.5+R=3.5 R, T_(2)=1`
`T_(2)=[(R_(2))/(R_(1))]^(3//2)xxT_(1)=24[(3.5R)/(7R)]^(3//2)= (24)/(2 sqrt(2))= 6sqrt(2) h`