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A wire of length L and radius r is clamp...

A wire of length L and radius r is clamped at one end. On stretching the other end of the wire with a force F, the increase in its length is `l`. If another wire of same material but of length 2L and radius 2r is stretched with a force 2F, the increase in its length will be

A

`(l)/(4)`

B

`(l)/(2)`

C

l

D

2l

Text Solution

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The correct Answer is:
To solve the problem, we will use the concept of Young's modulus, which relates stress and strain in materials. ### Step-by-Step Solution: 1. **Understanding the Problem**: We have two wires made of the same material. The first wire has a length \( L \) and radius \( r \), and when a force \( F \) is applied, it stretches by an amount \( l \). The second wire has a length \( 2L \) and radius \( 2r \), and we need to find the increase in length when a force \( 2F \) is applied. 2. **Young's Modulus Definition**: Young's modulus \( Y \) is defined as: \[ Y = \frac{\text{Stress}}{\text{Strain}} \] where: - Stress \( = \frac{F}{A} \) (Force per unit area) - Strain \( = \frac{\Delta L}{L} \) (Change in length per original length) 3. **Calculate Young's Modulus for the First Wire**: For the first wire: - Area \( A = \pi r^2 \) - Stress \( = \frac{F}{\pi r^2} \) - Strain \( = \frac{l}{L} \) Therefore, the Young's modulus \( Y \) for the first wire is: \[ Y = \frac{F / \pi r^2}{l / L} = \frac{F L}{\pi r^2 l} \] 4. **Calculate Young's Modulus for the Second Wire**: For the second wire: - Length \( = 2L \) - Radius \( = 2r \) - Area \( A = \pi (2r)^2 = 4\pi r^2 \) - Stress \( = \frac{2F}{4\pi r^2} = \frac{F}{2\pi r^2} \) - Let the increase in length be \( l' \), then Strain \( = \frac{l'}{2L} \) Therefore, the Young's modulus \( Y \) for the second wire is: \[ Y = \frac{(F / (2\pi r^2))}{(l' / (2L))} = \frac{F L}{\pi r^2 l'} \] 5. **Equating Young's Modulus**: Since both wires are made of the same material, their Young's moduli are equal: \[ \frac{F L}{\pi r^2 l} = \frac{F L}{\pi r^2 l'} \] 6. **Simplifying the Equation**: Canceling out common terms: \[ l = l' \] 7. **Conclusion**: The increase in length \( l' \) of the second wire is equal to the increase in length \( l \) of the first wire. Therefore, the increase in length of the second wire is: \[ l' = l \] ### Final Answer: The increase in length of the second wire is \( l \). ---

To solve the problem, we will use the concept of Young's modulus, which relates stress and strain in materials. ### Step-by-Step Solution: 1. **Understanding the Problem**: We have two wires made of the same material. The first wire has a length \( L \) and radius \( r \), and when a force \( F \) is applied, it stretches by an amount \( l \). The second wire has a length \( 2L \) and radius \( 2r \), and we need to find the increase in length when a force \( 2F \) is applied. 2. **Young's Modulus Definition**: ...
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