Two parallel and opposite forces each 5000 N are applied tangentially to the upper and lower faces of a cubical metal block of side 25 cm. the angle of shear is (The shear modulus of the metal is 80 Gpa)

Options

A. `10^(-4) rad`
B. `10^(-5) rad`
C. `10^(-6) rad`
D. `10^(-7) rad`

Answer

C

Explanation

Here, F = 5000 N
`L = 25 cm = 25 xx 10^(-2)m`
`A= (25xx 10^(-2)m)^(2) = 625 xx 10^(-4)m^(2)`
`eta = 80 GPa = 80xx 10^(9) Pa`
Angle of shear, `theta =(F)/(A eta) = (5000)/(625 xx 10^(-4)xx80xx 10^(9)) = 10^(-6)rad`