A sphere contracts in volume by `0.01%` when taken to the bottom of sea `1km` keep. The bulk modulus of the material of the sphere is (Given density of sea water may be taken as `1.0xx10^3kgm^-3`).

Options

A. `4.9xx10^(10) N m^(-2)`
B. `9.8 xx 10^(10)N m^(-2)`
C. `4.9xx10^(9) N m^(-2)`
D. `9.8 xx 10^(9)N m^(-2)`

Answer

B

Explanation

Here, `(DeltaV)/(V) = (0.01)/(100), h = 1 km = 10^(3)m`
`rho = 1.0 xx 10^(3) kg m^(-3)`
` P = hrhog = 10^(3) xx 1xx10^(3)xx Nm^(-2)`
`therefore B = (P)/(DeltaV//V) = (9.8 xx 10^(6) xx 100)/(0.01) = 9.8 xx 10^(10) N m^(-2)`