The bulk modulus of water if its volume changes from `100 litres` to `99.5 litres` under a pressure of `100atm` is (Take `1atm=10^5Nm^-2`)

Options

A. `2xx10^(7)Nm^(-2)`
B. `2xx10^(8)Nm^(-2)`
C. `2xx10^(9)Nm^(-2)`
D. `2xx10^(10)Nm^(-2)`

Answer

C

Explanation

According to definition of bulk modulus, `B = - (P)/(DeltaV//V)`
Here, P = 100 atm `= 100 xx 10^(5) N m^(-2) = 10^(7) N m^(-2)`
`DeltaV = (99.5 -100)` litre = - 0.5 litre
V= 100 litre
`therefore B =(10^(7) Nm^(-2))/(("-0.5 liter"//"100 liter"))= 2xx 10^(9)N m^(-2)`