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With what minimum acceleration can a fir...

With what minimum acceleration can a fireman slide down a rope whose breaking strength is `(2//3)` of his weight?

A

`(g)/(2)`

B

`(2)/(3)g`

C

`(3)/(2)g`

D

`(g)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
D

Net downward force in the string, ma = mg - T
But `T_("min") = (2)/(3) mg " " therefore " "ma_("min") = mg - (2)/(3) mg a_("min") = g - (2)/(3) g = (g)/(3)`
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