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The adjacent graph shows the extension D...

The adjacent graph shows the extension `Deltal` of a wire of length 1m, suspended from the f top of a roof at one end and with a loaf w connected to the other end. If the cross-sectional area of the wire is `10^(6) m^(2)` calculate the young's modulus of the material of the wire .

A

`2xx10^(11) N //m^(2)`

B

`2xx10^(-11) N //m^(2)`

C

`3xx10^(-12) N//m^(2)`

D

`2x10^(-13)N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Y=(F//A)/(Deltal//l)= (Fl)/(ADelta l)`
`Y = (20xx 1)/(10^(-6) xx 10^(-4)) = 2 xx 10^(11) Nm^(2)" " therefore Y=2 xx 10^(11)Nm^(-2)`
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