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Two blocks of masses 1 kg and 2 kg are c...

Two blocks of masses `1 kg` and `2 kg` are connected by a metal wire going over a smooth pulley as shown in figure.
The breaking stress of the metal is `(40//3pi)xx10^(6)N//m^(2)`. If `g=10ms^(-2)`, then what should be the minimum radius of the wire used if it is not to break?

A

0.5 mm

B

1 mm

C

1.5 mm

D

2 mm

Text Solution

Verified by Experts

The correct Answer is:
B
`T = (2m_(1)m_(2))/(m_(1)+m_(2)) g = (2xx1xx2)/(1+2) xx 10 N = (40)/(3)N`
If r is the minimum radius, then
Breaking stress `= ((40)/(3))/((pir^(2))) or (40)/(3pi) xx 10^(6) = (40)/(3pir^(2))`
or ` r^(2) = (1)/(10^(6)) or r = (1)/(10^(3))m = 1 mm`
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