Home
Class 11
PHYSICS
A liquid flows through a horizontal tube...

A liquid flows through a horizontal tube as shown in figure. The velocities of the liquid in the two sections, which have areas of cross-section `A_(1)` and `A_(2)` and `v_(1)` and `v_(2)` respectively. The difference in the levels of the liquid in the two vertical tubes is `h`. then

A

`v_(2)^(2)-v_(1)^(2)=2gh`

B

`v_(2)^(2)+v_(1)^(2)=2gh`

C

`v_(2)^(2)-v_(1)^(2)=gh`

D

`v_(2)^(2)+v_(1)^(2)=gh`

Text Solution

Verified by Experts

The correct Answer is:
A
Let `rho` be density of liquid flowing in the tube. `A_(1)v_(1)=A_(2)v_(2)`
`(v_(1))/(v_(2))=(A_(2))/(A_(1))`
According to Bernoulli's equation for horizontal flow of liquid,
`P_(1) +(1)/(2)rhoV_(1)^(2)=P_(2)+(1)/(2)rhov_(2)^(2)`
`P_(1)-P_(2)=(1)/(2)(rhov_(2)^(2)-rhov_(1)^(2))`
`hrhog=(1)/(2)rho(v_(2)^(2)-v_(1)^(2))" "(because P_(1)-P_(2)=hrhog)`
`v_(2)^(2)-v_(1)^(2)=2hg`
Promotional Banner

Topper's Solved these Questions

  • MECHANICAL PROPERTIES OF FLUIDS

    NCERT FINGERTIPS|Exercise Viscosity|15 Videos

  • MECHANICAL PROPERTIES OF FLUIDS

    NCERT FINGERTIPS|Exercise Reynolds Number|4 Videos

  • MECHANICAL PROPERTIES OF FLUIDS

    NCERT FINGERTIPS|Exercise Streamline Flow|7 Videos

  • LAWS OF MOTION

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

  • MECHANICAL PROPERTIES OF SOLIDS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross section A_(1) and A_(2) are v_(1) and v_(2) respectively. The difference in the levels of the liquid in the two vertical tubes is h . Then

An incompressible liquid flows through a horizontal tube as shown in the figure. Then the velocity 'v' of the fluid is:

An incompressible liquid flows through a horizontal tube LMN as shown in the figure. Then the velocity V of the liquid throught he tube N is:

From a horizontal tube with area of cross-section A_(1) and A_(2) as shosn in fiugre liquid is flowing in the level of the liauid in the two veritcal tunes is h.

Water flows through a horizontal tube as shown in figure. If the difference of heights of water colun in the vertical tubes is 2 cm and the area of cross section at A and B are 4cm^2 and 2cm^2 respectively, find the rate of flow of water across any section.

An incompressible, non-viscous liquis of density r flows through a horizontal tube as shown below. The flow condition is steady. Area of cross section at A and B are a_(1) and a_(2) respectively. The height difference of liquid in two tubes inserted at A and B is h.

Fig, shows a U-tube of uniform cross-sectional area A accelerated with acceleration a as shown. If d is the seperation between the limbs. Then the difference in the levels of the liquid in the U-tube is

The mass of the liquid flowing per second per unit area of cross section of the tube is proportional to P^(x) and v^(y) , where P is the pressure difference and v is the velocity , then the relation between x and Y is

Water flows through the tubes shown in figure. The areas of cross-section of the wide and the narrow portions of the tube are 5 cm^(2) and 2 cm^(2) respectively. The rate of flow of water through the tube is 500 cm^(3)//s . Find the difference of mercury levels in the U-tube.