A balloon contains `1500 m^(3)` of helium at `27^(@)C` and 4 atmospheric pressue. The volume of helium at `-3^(@)C` themperature and 2 atmospheric pressure will be

Options

A. `1500m^(3)`
B. `1700m^(3)`
C. `1900m^(3)`
D. `2700m^(3)`

Answer

D

Explanation

Here, `V_(1)=1500m^(3),T_(1)=27^(@)C=300K`
`P_(1)=4atm,T_(2)= -3^(@)C=270K`
`P_(2)=2 atm`
According to ideal gas equation
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
`thereforeV_(2)=(P_(1)V_(1))/(T_(1))xx(T_(2))/(P_(2))=(4xx1500xx270)/(300xx2)=2700m^(3)`