A gas is filled in a container at pressure `P_(0)`. If the mass of molecules is halved and their rms speed is doubled, then the resultant pressure would be

Options

A. `2P_(0)`
B. `4P_(0)`
C. `(P_(0))/(4)`
D. `(P_(0))/(2)`

Answer

A

Explanation

Using, `P=1/3rhov_(rms)^(2)=1/3(mN)/(V)v_(rms)^(2)`
`thereforePpropmv_(rms)^(2)`
As m is halved and `v_(rms)` is doubled then P becomes twice or `2P_(0).`