A vessel is filled with a gas at a pressure of 76 cm of mercury at a certain temperature. The mass of the gas is increased by 50% by introducing more gas in the vessel at the same temperature. Find the resultant pressure of the gas.

Options

A. 76 cm of mercury
B. 108 cm of mercury
C. 112 cm mercury
D. 114 cm of mercury

Answer

D

Explanation

Pressur exerted by a gas.
`P=1/2M/Vv_(av)^(2)`
Since the temperature T is kept constant, `v_(av)^(2)` and V are also constant.
`thereforePpropMor (P_(2))/(P_(1))=(M_(2))/(M_(1))`
According to the question,
`therefore(P_(2))/(76)=([M_(1)+((50)/(100))M_(1)])/M_(1)=3/2`
`impliesP_(2)=3/2xx76=114` cm of marcury.